Edition 4
1. P is a point on the plane of the square ABCD such that each of PAB, PBC, PCD and PDA is an isosceles triangle. How many possible positions are there for such a point P?
- (A) 9
- (B) 17
- (C) 1
- (D) 5
- (E) 10
2. A man borrows Rs. 21000 at 10% compound interest. How much he has to pay annually at the end of each year, to settle his loan in two years?
- (A) Rs. 12000
- (B) Rs. 12100
- (C) Rs. 12200
- (D) Rs. 12300
- (E) Rs. 12310
3. Let f be any function. About which line are the graphs of y = f(x − 1) and y = f(−x + 1) symmetric?
- (A) y = 0
- (B) x = 1
- (C) x = −1
- (D) x = 0
- (E) x = 2
Problem #2) Solution :
B D=x cm;;
C o s
Or (A B ^2+ B D ^2-A D ^2)/(2 * A B* B D)=(A C ^2+C D ^2-A D ^2)/(2* A C * C D);
Or ( 1 7^2 +x ^2 -1 5 ^2/(2* 17 * x)=(1 7^2 + 4 ^2-1 5 ^2)/(2 * 17* 4);
Or (64+ x^2)/x= (80)/4=20;
Or 64+ x^2=20 *x; or x=4 or 16 ;
Admissible value of x=16B D= x cm=16 cm
Thank you sir for another solution
Please explain this answer.
Solution of problem1.
First we will measure 3 conis each side.
Case1 – if balance is eqall we will measure two out of 3 coins putting one on each side, thus we will get the heavier one.
Case 2 – if one side is heavier them we will take 2 coins of the heavier side and measure by putting one each side, thus we can find the heavier one.
Solution of problem1.
First we will measure 3 conis each side.
Case1 – if balance is eqall we will measure two out of 3 coins putting one on each side, thus we will get the heavier one.
Case 2 – if one side is heavier them we will take 2 coins of the heavier side and measure by putting one each side, thus we can find the heavier one.
Thank you so much Sir
Question 1 solution :
(c)
As 10 houses have less than 6rooms, they are to be excluded.
Given,
4 houses have more than 8 rooms .
Therefore, number of houses having either less than 6 or greater than 8 rooms = 10 + 4 = 14.
The remaining houses, that is 11 houses fulfill the above mentioned criteria.